我可以知道我的文字再word里是否换行吗？他有几行？

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1

我可以知道我的文字再word里是否换行吗？他有几行？一段话他在word里有几行，这个aspose是否有相关api?

2

@xl1,

下面的代码将打印Word文档中每个段落的行数。

Document document = new Document("C:\\Temp\\word.docx");

var collector = new LayoutCollector(document);
var it = new LayoutEnumerator(document);

foreach (Paragraph paragraph in document.GetChildNodes(NodeType.Paragraph, true))
{
    var paraBreak = collector.GetEntity(paragraph);

    object stop = null;
    var prevItem = paragraph.PreviousSibling;
    if (prevItem != null)
    {
        var prevBreak = collector.GetEntity(prevItem);
        if (prevItem is Paragraph)
        {
            it.Current = collector.GetEntity(prevItem); // para break
            it.MoveParent();    // last line
            stop = it.Current;
        }
        else if (prevItem is Table)
        {
            var table = (Table)prevItem;
            it.Current = collector.GetEntity(table.LastRow.LastCell.LastParagraph); // cell break
            it.MoveParent();    // cell
            it.MoveParent();    // row
            stop = it.Current;
        }
        else
        {
            throw new Exception();
        }
    }

    it.Current = paraBreak;
    it.MoveParent();

    // We move from line to line in a paragraph.
    // When paragraph spans multiple pages the we will follow across them.
    var count = 1;
    while (it.Current != stop)
    {
        if (!it.MovePreviousLogical())
            break;
        count++;
    }

    const int MAX_CHARS = 16;
    var paraText = paragraph.GetText();
    if (paraText.Length > MAX_CHARS)
        paraText = $"{paraText.Substring(0, MAX_CHARS)}...";

    Console.WriteLine($"Paragraph '{paraText}' has {count} line(-s).");
}

如果这不是您要询问的内容，请通过提供用例的完整详细信息进一步详细说明您的询问。 这将有助于我们了解您的情况，并且我们将可以更好地解决您的问题。

3

额，我不懂js，请问有java的嘛？

4

@xl1,

我在上一篇文章中共享的C＃代码的Java等效代码如下：

Document doc = new Document("C:\\Temp\\Queries.docx");

LayoutCollector collector = new LayoutCollector(doc);
LayoutEnumerator it = new LayoutEnumerator(doc);

for (Paragraph paragraph : (Iterable<Paragraph>) doc.getChildNodes(NodeType.PARAGRAPH, true)) {
    Object paraBreak = collector.getEntity(paragraph);

    Object stop = null;
    com.aspose.words.Node prevItem = paragraph.getPreviousSibling();
    if (prevItem != null) {
        Object prevBreak = collector.getEntity(prevItem);
        if (prevItem.getNodeType() == NodeType.PARAGRAPH) {
            it.setCurrent(collector.getEntity(prevItem)); // para break
            it.moveParent();    // last line
            stop = it.getCurrent();
        } else if (prevItem.getNodeType() == NodeType.TABLE) {
            Table table = (Table) prevItem;
            it.setCurrent(collector.getEntity(table.getLastRow().getLastCell().getLastParagraph())); // cell break
            it.moveParent();    // cell
            it.moveParent();    // row
            stop = it.getCurrent();
        } else {
            throw new Exception();
        }
    }

    it.setCurrent(paraBreak);
    it.moveParent();

    // We move from line to line in a paragraph.
    // When paragraph spans multiple pages the we will follow across them.
    int count = 1;
    while (it.getCurrent() != stop) {
        if (!it.movePreviousLogical())
            break;
        count++;
    }

    int MAX_CHARS = 16;
    String paraText = paragraph.getText();
    if (paraText.length() > MAX_CHARS)
        paraText = paraText.substring(0, MAX_CHARS) + "...";

    System.out.println("Paragraph '" + paraText + "' has " + count + " line(-s).");
}