When I open a Worksheet I calculate the number of rows in the sheet as follows:

int rows = ws.Cells.MaxRow - ws.Cells.MinRow;

This works almost all the time. I have one spreadsheet that is returning a MaxRow value of 1574 and a MinRow value of 1. This results in a rows value of 1573, which is incorrect. The total number of rows is 1574.

What am I doung wrong? Should I not be using the formula above for retrieving the number of rows and just use MaxRows?

Thanks,

-JC

# MinRow

**jcioffari**#1

**Laurence**#2

MaxRow and MinRow properties return the max and min row index. So the row number should be:

int rows = ws.Cells.MaxRow - ws.Cells.MinRow + 1;

I think in your file, generally the MinRow returns 0. So your code works in most of time but it fails when MinRow doesn't return 0.

**jcioffari**#3

Should I use the same formula to calculate columns?

int cols = ws.Cells.MaxColumn + ws.Cells.MinColumn + 1; <== ???

I haven’t had the issue with Column yet, but should I change the formula?

Thanks.

**jcioffari**#4

Can MinRow ever return > 1? Would a formulat like this:

int rows = ws.Cells.MaxRow + ws.Cells.MinRow;

work better in most cases?

Same question for MinColumn…

Thanks.

**Laurence**#5

Please use:

int rows = ws.Cells.MaxRow - ws.Cells.MinRow + 1;

int cols = ws.Cells.MaxColumn - ws.Cells.MinColumn + 1;

**jcioffari**#6

Ok, I implemented your suggestion. But…

In most cases, all but one, when I load the worksheet into my Grid I am getting an extra blank column and row shown. Should I only add one if the Min values are greater than 0?

Thanks.

**Laurence**#7

Could you please post your file and sample code here? Is the extra blank column and row show at the start of your grid?

**Laurence**#9

You may set style in the end of row or column in your excel file. Please delete the blank end row/column in your excel file.

**jcioffari**#10

I have a spreadsheet that has 1655 rows. The MaxRow is returning 1654. The MinRow is returning 3.

The formula MaxRow - MinRow + 1 doesn't work. Why is MinRow 3??

I can't attach the spreadsheet as it contains sensitive data.

Any help ASAP would be appreciated.

Thanks,

-Steven Perry