If I have a single, one time date.... is there a way to represent that with a pattern?
Maybe this?
DTSTART:20040101T103000
RRULE:FREQ=DAILY;COUNT=1
Yes this pattern will work for a single occurrence.
Romank,
You may want to check this. I think there is a bug with the "Count=1".
I used
DTSTART:19770113T010000
RRULE:FREQ=DAILY;COUNT=1
Which, according to our discussion would give 1 instance, on Jan 13th, 1977.
The counter I set, was over 10,000 entries (aka, .GenerateOccurences).
I had to revert to using the "Until" date of the same date.
DTSTART:19770113T010000
RRULE:FREQ=DAILY;UNTIL=19770113T000000Z
It did this behavior, if I created the rules programatically, or using a hardcoded iCalendarExpression.
C# code:
DateTime occurenceDate = new DateTime(1977, 1, 13);
RecurrencePattern p = new RecurrencePattern();
RecurrenceRule r = new RecurrenceRule();
p.StartDate = occurenceDate;
r.Until = occurenceDate; //see note below
r.Frequency = Aspose.iCalendar.Frequency.Daily;
//r.Count = 1; // this is the issue, uncomment this ... and comment out r.Until (above) .... OR leave r.Until intact...
p.RRules.Add (r);
string ical = p.ToiCalendar();
System.DateTime[] dts = FindDates(ical);
//--------------------------
I have a "FindDates" routine also:
private static System.DateTime[] FindDates(string calendarExpression)
{
RecurrencePattern p = new RecurrencePattern(calendarExpression);
foreach(RecurrenceRule r in p.RRules)
{
Console.WriteLine(r.Until);
DateCollection recurrenceDates = p.GenerateOccurrences();
if (recurrenceDates.Count > 100) // this number is ~alot
{
Console.WriteLine("");
}
else
{
Console.WriteLine("");
}
System.DateTime[] dates = (DateTime[]) recurrenceDates.ToArray(typeof(DateTime));
return dates;
}